A school playground is divided by a 2 m wide path which is parallel to the width of the playground, and a 3 m wide path which is parallel to the length of the ground (Fig. 9.60). If the length and width of the playground are 120 m and 80 m respectively, find the area of the remaining playground.
Solution:
Given, the length and width of a school playground are 120 m and 80 m.
The playground is divided by a 2 m wide path parallel to the width of the ground.
The playground is divided by a 3 m wide path parallel to the length of the ground.
We have to find the remaining area of the playground.
Area of rectangle = length × width
Considering school playground,
Length = 120 m
Width = 80 m
Area = 120(80)
= 9600 m²
Considering 2 m wide path parallel to the width of the ground,
Length = 80 - 3 = 77 m
Width = 2 m
Area = 77(2)
= 154 m²
Considering 3 m wide path parallel to the length of the ground,
Length = 120 m
Width = 3 m
Area = 120(3)
= 360 m²
Area of path = 154 + 360
= 514 m²
Remaining area of the playground = area of playground - area of path
= 9600 - 514
= 9086 m²
Therefore, the remaining area of the playground is 9086 m².
✦ Try This: If the difference between the circumference and diameter of a circle is 30 cm then what is the radius of the circle?
☛ Also Check: NCERT Solutions for Class 7 Maths Chapter 11
NCERT Exemplar Class 7 Maths Chapter 9 Problem 115
A school playground is divided by a 2 m wide path which is parallel to the width of the playground, and a 3 m wide path which is parallel to the length of the ground (Fig. 9.60). If the length and width of the playground are 120 m and 80 m respectively, find the area of the remaining playground.
Summary:
A school playground is divided by a 2 m wide path which is parallel to the width of the playground, and a 3 m wide path which is parallel to the length of the ground (Fig. 9.60). If the length and width of the playground are 120 m and 80 m respectively, the area of the remaining playground is 9086 m².
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