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A right triangle with sides 6 cm, 8 cm and 10 cm is revolved about the side 8 cm. Find the volume and the curved surface of the solid so formed.

Solution:

Given, a right triangle with sides 6 cm, 8 cm and 10 cm

The right triangle is revolved about the same side 8 cm

We have to find the volume and curved surface area of the solid so formed

When the right triangle is revoked about the side 8 cm, the solid so formed is a cone with height 8 cm, radius of base 6 cm and slant height 10 cm.

Volume of cone = 1/3 πr²h

Where, r is the radius of the cone

h is the height of the cone

Given, r = 6 cm

h = 8 cm

So, volume = 1/3 π(6)²(8)

= (22/7)(12)(8)

= 22(96)/7

= 2112/7

= 301.71 cm³

Curved surface area = πrl

Given, r = 6 cm

l = 10 cm

Curved surface area = (22/7)(6)(10)

= 220(6)/7

= 1320/7

= 188.57 cm²

Therefore, the volume and the curved surface of the solid is 301.71 cm³ and 188.57 cm².

✦ Try This: A right triangle with sides 3 cm, 4 cm and 5 cm is revolved about the side 4 cm. Find the volume and the curved surface of the solid so formed.

☛ Also Check: NCERT Solutions for Class 9 Maths Chapter 13

NCERT Exemplar Class 9 Maths Exercise 13.3 Problem 10

A right triangle with sides 6 cm, 8 cm and 10 cm is revolved about the side 8 cm. Find the volume and the curved surface of the solid so formed.

Summary:

A right triangle with sides 6 cm, 8 cm and 10 cm is revolved about the side 8 cm. The volume and the curved surface of the solid so formed is 301.71 cm³ and 188.57 cm²

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