A perfect square number having n digits where n is even will have square root with
a. n+1 digit
b. n/2 digit
c. n/3 digit
d. (n+1)/2 digit

Solution:

Given, a perfect square number has n digits.

n is even

We have to find the digits the square root will have.

If a perfect square is of n digits, then its square root will have n/2 digit if n is even.

Example: consider a perfect square 36

Number of digits, n = 2

n is even.

Square root of 36 = √36 = 6

n/2 = 2/2 = 1

Number of digits in square root = 1

Therefore, the square root will have n/2 digits.

✦ Try This: A perfect square number having n digits where n is odd will have square root with a. n+1 digit, b. n/2 digit, c. n/3 digit, d. (n+1)/2 digit

☛ Also Check: NCERT Solutions for Class 8 Maths

NCERT Exemplar Class 8 Maths Chapter 3 Problem 21

A perfect square number having n digits where n is even will have square root with, a. n+1 digit, b. n/2 digit, c. n/3 digit, d. (n+1)/2 digit

Summary:

A perfect square number having n digits where n is even will have square root with n/2 digits

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