A perfect square can never have the following digit at one’s place.
a. 1
b. 6
c. 5
d. 3

Solution:

We have to find if a perfect square can have 1, 6, 5 or 3 at one’s place or not.

The unit digit of a perfect square can be only 0, 1, 4, 5, 6 or 9.

The square of a number having: 

1 or 9 at the unit's place ends in 1. 

2 or 8 at the unit's place ends in 4. 

3 or 7 at the unit's place ends at 9. 

4 or 6 at the unit's place ends at 6. 

5 at the unit's place ends in 5.

From the above statement,

It is clear that a perfect square can have 1, 5, 6 at the unit's place.

Therefore, 3 can never be at the unit's place of a perfect square.

✦ Try This: A perfect square can never have the following digit at one’s place. a. 2, b. 4, c. 6, d. 0

☛ Also Check: NCERT Solutions for Class 8 Maths

NCERT Exemplar Class 8 Maths Chapter 3 Sample Problem 5

A perfect square can never have the following digit at one’s place. a. 1, b. 6, c. 5, d. 3

Summary:

A perfect square can never have 3 at one’s place

☛ Related Questions:

• The value of √(176 + √2401) is, a. 14, b. 15, c. 16, d. 17
• Given that √5625 =75, the value of √0.5625 + √56.25 is, a. 82.5, b. 0.75, c. 8.25, d. 75.05
• There are __________ perfect squares between 1 and 50. Fill in the blanks to make the statement true