A die is thrown 1000 times and the outcomes were recorded as follows :
Outcome 1 2 3 4 5 6
Frequency 180 150 160 170 150 190
If the die is thrown once more, then the probability that it shows 5 is :
a. 9/50
b. 3/20
c. 4/25
d. 7/25
Solution:
It is given that
A die is thrown 1000 times
Here
Probability showing 5 is P(E) = Number of times 5 occurs/ Total number of throws
Substituting the values
P(E) = 150/1000
So we get
P(E) = 3/20
Therefore, the probability that it shows 5 is 3/20.
✦ Try This: A die is thrown 1000 times and the outcomes were recorded as follows :
|
Outcome |
1 |
2 |
3 |
4 |
5 |
6 |
|
Frequency |
120 |
130 |
140 |
150 |
160 |
170 |
If the die is thrown once more, then the probability that it shows 4 is :
It is given that
A die is thrown 1000 times
Here
Probability showing 4 is P(E) = Number of times 4 occurs/ Total number of throws
Substituting the values
P(E) = 150/1000
So we get
P(E) = 3/20
Therefore, the probability that it shows 5 is 3/20.
☛ Also Check: NCERT Solutions for Class 9 Maths Chapter 14
NCERT Exemplar Class 9 Maths Exercise 14.1 Sample Problem 3
A die is thrown 1000 times and the outcomes were recorded as follows : Outcome 1 2 3 4 5 6 Frequency 180 150 160 170 150 190. If the die is thrown once more, then the probability that it shows 5 is : a. 9/50, b. 3/20, c. 4/25, d. 7/25
Summary:
A die is thrown 1000 times and the outcomes are recorded. If the die is thrown once more, then the probability that it shows 5 is 3/20
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