A die has two faces each with number '1', three faces each with number ' 2 ' and one face with number '3'. If die is rolled once, determine
(i) P (2)  (ii) P (1 or 3)  (iii) P (not 3)

Solution:

Total number of faces = 6

We know that the probability of an event = (Number of favourable outcomes) / (Total number of events)

(i) Number of faces with number '2' = 3

Therefore,

P (2) = 3/6 = 1/2

(ii) Since,

P (1 or 3) = P (not 2)

= 1 - P (2)

= 1 - 1/2 (from (i))

= 1/2

(iii) Number of faces with number '3' = 1

Therefore,

P (3) = 1/6

Thus,

P (not 3) = 1 - P (3)

= 1 - 1/6

= 5/6

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NCERT Solutions Class 11 Maths Chapter 16 Exercise ME Question 3

A die has two faces each with number '1', three faces each with number ' 2 ' and one face with number '3'. If die is rolled once, determine (i) P (2) (ii) P (1 or 3) (iii) P (not 3)

Summary:

A die has two faces each with number '1' , three faces each with number ' 2 ' and one face with number '3'. If die is rolled once, then (i) P(2) = 1/2 (ii) P(1 or 3) = 1/2 (iii) P(not 3) = 5/6