A die has its six faces marked 0, 1, 1, 1, 6, 6. Two such dice are thrown together and the total score is recorded. What is the probability of getting a total of 7

Solution:

Given, a die has its six faces marked 0, 1, 1, 1, 6, 6. 0, 1, 1, 1, 6, 6.

Two such dice are thrown together and the total score is recorded.

We have to find the probability of getting a total of 7.

When two dice are thrown, the possible outcomes are

(0,0) (0,1) (0,1) (0,1) (0,6) (0,6)

(1,0) (1,1) (1,1) (1,1) (1,6) (1,6)

(1,0) (1,1) (1,1) (1,1) (1,6) (1,6)

(1,0) (1,1) (1,1) (1,1) (1,6) (1,6)

(6,0) (6,1) (6,1) (6,1) (6,6) (6,6)

(6,0) (6,1) (6,1) (6,1) (6,6) (6,6)

Number of possible outcomes = 36

Favourable outcome = total of 7

= (1,6) (1,6) (1,6) (1,6) (1,6) (1,6) (6,1) (6,1) (6,1) (6,1) (6,1) (6,1)

Number of favourable outcomes = 12

Probability = number of favourable outcomes / number of possible outcomes

Probability = 12/36

= 1/3

Therefore, the probability of getting a total of 7 is 1/3.

✦ Try This: A die has its six faces marked 0, 1, 1, 1, 6, 6. Two such dice are thrown together and the total score is recorded. What is the probability of getting a total of 12?

☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 14

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NCERT Exemplar Class 10 Maths Exercise 13.3 Problem 39(ii)

A die has its six faces marked 0, 1, 1, 1, 6, 6. Two such dice are thrown together and the total score is recorded. What is the probability of getting a total of 7

Summary:

A die has its six faces marked 0, 1, 1, 1, 6, 6. Two such dice are thrown together and the total score is recorded. The probability of getting a total of 7 is 1/3

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