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A canal is 300 cm wide and 120 cm deep. The water in the canal is flowing with a speed of 20 km/h. How much area will it irrigate in 20 minutes if 8 cm of standing water is desired

Solution:

Given a canal 300 cm wide and 120 cm deep.

Water in the canal is flowing with a speed of 20 km/hr

We have to find the area to irrigate in 20 minutes if 8 cm of standing water is desired.

Volume of the water flowing in the canal in one hour = Width × depth × speed of the water

Width = 300 cm = 300/100 = 3 m

Depth = 120 cm = 120/100 = 1.2 m

Speed of water = 20 km/hr = 20 × 1000 m³/hr

Volume of water in the canal that flows out in one hour = 3 × 1.2 × 20000

= 72000 m³

1 hour = 60 mins

Volume of the water that flows out in 20 minutes = 72000 × 20/60

= 72000 × 1/3

= 24000 m³

Given, 8 cm of standing is desired.

Depth of water = 8 cm

= 8/100 m

Area of irrigation = volume/depth

= 24000/(8/100)

= 3000(100)

= 300000 m²

1 hectare = 10000 m²

Area of irrigation = 30 hectares.

Therefore, the area irrigated by the water flowing out of the canal in 20 mins if 8 cm of standing water is desired is 30 hectares.

✦ Try This: A canal is 500 cm wide and 180 cm deep. The water in the canal is flowing with a speed of 10 km/h. How much area will it irrigate in 40 minutes if 9 cm of standing water is desired?

☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 13

NCERT Exemplar Class 10 Maths Exercise 12.3 Sample Problem 3

A canal is 300 cm wide and 120 cm deep. The water in the canal is flowing with a speed of 20 km/h. How much area will it irrigate in 20 minutes if 8 cm of standing water is desired

Summary:

A canal is 300 cm wide and 120 cm deep. The water in the canal is flowing with a speed of 20 km/h. The area irrigated in 20 minutes if 8 cm of standing water is desired is 30 hectares

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