A box contains 5 red marbles, 8 white marbles and 4 green marbles. One marble is taken out of the box at random. What is the probability that the marble taken out will be
(i) red ?   (ii) white ?   (iii) not green?

Solution:

Let's find out the probability of getting red, white, and green marble by using the formula

Probability = Number of possible outcomes/Total number of favorable outcomes.

Using the formula of the sum of complementary event, we will find out the probability of not getting the green ball.

P (E) + P (not E) = 1

Number of red balls in a bag = 5

Number of white balls in a bag = 8

Number of green balls in a bag = 4

Total number of balls = 5 + 8 + 4 = 17

(i) Probability of drawing red ball = 5/17

(ii) Probability of drawing white ball = 8/17

(iii) Probability of drawing a green ball = 4/17

Let the probability of not getting a green ball be P (not E)

P (not E) = 1 - P (E)

= 1 - 4/17

= 13/17

☛ Check: NCERT Solutions for Class 10 Maths Chapter 15

Video Solution:

A box contains 5 red marbles, 8 white marbles and 4 green marbles. One marble is taken out of the box at random. What is the probability that the marble taken out will be (i) red ? (ii) white ? (iii) not green?

NCERT Solutions for Class 10 Maths Chapter 15 Exercise 15.1 Question 9

Summary:

If a box contains 5 red marbles, 8 white marbles and 4 green marbles, and one marble is taken out of the box at random, then the probability that the marble taken out will be red, white, and not green are 5/17, 8/17, and 13/17 respectively.

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