500 persons are taking a dip into a cuboidal pond which is 80 m long and 50 m broad. What is the rise of water level in the pond, if the average displacement of the water by a person is 0.04m³
Solution:
Given, a cuboidal pond has dimensions 80 m long and 50 m broad.
500 persons are taking a dip into the pond.
Average displacement of water by a person is 0.04 m³.
We have to find the rise of water level in the pond.
Average displacement by 500 persons = 500(0.04)
= 20 m³
Volume of water raised in the pond = 20 m³
Volume of water rise in the cuboidal pond = length × width × depth
= 80 × 50 × h
= 4000 h
Now, the volume of water rise in the pond = average displacement of water by 500 persons.
4000 h = 20
h = 20/4000
h = 2/400
h = 1/200
h = 0.005 m
1 m = 100 cm
h = 0.005(100)
h = 0.5 cm
Therefore, the rise of water level in the pond is 0.5 cm
✦ Try This: 800 persons are taking a dip into a cuboidal pond which is 100 m long and 80 m broad. What is the rise of water level in the pond, if the average displacement of the water by a person is 0.06m³ ?
☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 13
NCERT Exemplar Class 10 Maths Exercise 12.4 Problem 10
500 persons are taking a dip into a cuboidal pond which is 80 m long and 50 m broad. What is the rise of water level in the pond, if the average displacement of the water by a person is 0.04m³
Summary:
500 persons are taking a dip into a cuboidal pond which is 80 m long and 50 m broad. The rise of water level in the pond, if the average displacement of the water by a person is 0.04m³ is 0.5 cm
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