A day full of math games & activities. Find one near you.

4 squares each of side 10 cm have been cut from each corner of a rectangular sheet of paper of size 100 cm × 80 cm. From the remaining piece of paper, an isosceles right triangle is removed whose equal sides are each of 10 cm length. Find the area of the remaining part of the paper.

Solution:

Given 4 squares each side 10 cm is cut from each corner of a rectangle sheet of paper of size 100 cm × 80 cm.

An isosceles triangle is removed from the remaining piece of paper whose equal sides are 10 cm length.

We have to find the remaining part of the paper.

Area of rectangular sheet = length × breadth

= 100(80)

= 8000 cm²

Area of one square = (side)²

= (10)²

= 100 cm²

So, area of 4 squares = 4(100) = 400 cm²

Area of triangle = 1/2 × base × height

Area of isosceles triangle = 1/2 × 10 × 10

= 10(5)

= 50 cm²

Area of the remaining part of the sheet = area of rectangular sheet - area of 4 squares - area of isosceles triangle

= 8000 - 400 - 50

= 7600 - 50

= 7550 cm²

Therefore, the area of the remaining part is 7550 cm².

✦ Try This: 3 squares each of side 15 cm have been cut from each corner of a rectangular sheet of paper of size 150 cm × 90 cm. From the remaining piece of paper, an isosceles right triangle is removed whose equal sides are each of 20 cm length. Find the area of the remaining part of the paper.

☛ Also Check: NCERT Solutions for Class 7 Maths Chapter 11

NCERT Exemplar Class 7 Maths Chapter 9 Problem 128

4 squares each of side 10 cm have been cut from each corner of a rectangular sheet of paper of size 100 cm × 80 cm. From the remaining piece of paper, an isosceles right triangle is removed whose equal sides are each of 10 cm length. Find the area of the remaining part of the paper.

Summary:

4 squares each of side 10 cm have been cut from each corner of a rectangular sheet of paper of size 100 cm × 80 cm. From the remaining piece of paper, an isosceles right triangle is removed whose equal sides are each of 10 cm length. The area of the remaining part of the paper is 7550 cm².

☛ Related Questions: