4/√3. Rationalise the denominator and hence evaluate by taking √2 = 1.414, √3 = 1.732 and √5 = 2.236, upto three places of decimal

Solution:

Given, the expression is 4/√3

We have to rationalise the denominator and evaluate the given expression.

To rationalise we have to take conjugate,

4/√3 = 4/√3 × √3/√3

= 4√3/3

Given, √3 = 1.732

4√3/3 = 4(1.732)/3

= 6.928/3

= 2.3093333

Therefore, 4/√3 = 2.309

✦ Try This: Rationalise the denominator of the following and hence evaluate by taking √2 = 1.414, √3 = 1.732 and √5 = 2.236, upto three places of decimal 5/√3

Given, the expression is 5/√3

We have to rationalise the denominator and evaluate the given expression.

To rationalise we have to take conjugate,

5/√3 = 5/√3 × √3/√3

= 5√3/3

Given, √3 = 1.732

5√3/3 = 5(1.732)/3

= 8.66/3

= 2.88667

Therefore, 5/√3 = 2.887

☛ Also Check: NCERT Solutions for Class 9 Maths Chapter 1

NCERT Exemplar Class 9 Maths Exercise 1.3 Problem 13(i)

4/√3. Rationalise the denominator and hence evaluate by taking √2 = 1.414, √3 = 1.732 and √5 = 2.236, upto three places of decimal

Summary:

On rationalising the denominator and evaluating the expression 4/√3 by taking √2 = 1.414, √3 = 1.732 and √5 = 2.236, we get 2.309

☛ Related Questions: