3a²b and -7ba² are ________ terms. Fill in the blanks to make the statement true.

Solution:

Given, 3a²b and -7ba² are ________ terms.

We have to fill in the blanks to make the statement true.

3a²b - 7ba² = 3a²b - 7a²b

By distributive property,

= (3 - 7)a²b

= -4a²b

Therefore, 3a²b and -7ba² are like terms.

✦ Try This: 5a²c and -9ca² are ________ terms. Fill in the blanks to make the statement true.

Given, 5a²c and -9ca² are ________ terms.

We have to fill in the blanks to make the statement true.

5a²c - 9ca² = 5a²c - 9a²c

By distributive property,

= (5 - 9)a²c

= -4a²c

5a²c and -9ca² have the same algebraic factors a²c.

Therefore, 5a²c and -9ca² are like terms.

☛ Also Check: NCERT Solutions for Class 7 Maths Chapter 12

NCERT Exemplar Class 7 Maths Chapter 10 Problem 19

3a²b and -7ba² are ________ terms. Fill in the blanks to make the statement true.

Summary:

3a²b and -7ba² are like terms.

☛ Related Questions:

• -5a²b and -5b²a are ________ terms. Fill in the blanks to make the statement true
• In the expression 2πr, the algebraic variable is ________. Fill in the blanks to make the statement . . . .
• Number of terms in a monomial is ________. Fill in the blanks to make the statement true