I have a total of ₹300 in coins of denomination ₹1, ₹2 and ₹5. The number of ₹2 coins is 3 times the number of ₹5 coins. The total number of coins is 160. How many coins of each denomination are with me?

Solution:

According to the question,

Let the number of ₹5 coins be x.

Then the number of ₹2 coins is 3x.

Number of ₹1 coin is = 160 - (x + 3x)

Let's tabulate the data as shown below,

From the table, we can see that the total value of all denominations is

160 - 4x + 6x + 5x = 160 + 7x

The total coin value is ₹300

Therefore, we shall equate the two to get the number of each denomination

160 - 4x + 6x + 5x = 300

160 + 7x = 300

7x = 140

x = 140/ 7 = 20

Thus the number of denominations of each note is:

☛ Check: NCERT Solutions for Class 8 Maths Chapter 2

Video Solution:

 I have a total of ₹300 in coins of denomination ₹1, ₹2 and ₹5. The number of ₹2 coins is 3 times the number of ₹5 coins. The total number of coins is 160. How many coins of each denomination are with me?

NCERT Solutions Class 8 Maths Chapter 2 Exercise 2.2 Question 15

Summary:

I have a total of ₹300 in coins of denomination ₹1, ₹2 and ₹5. The number of ₹2 coins is 3 times the number of ₹5 coins. The total number of coins of ₹1, ₹2, and ₹5 are 80, 60, and 20 respectively.

☛ Related Questions:

• Three consecutive integers are such that when they are taken in increasing order and multiplied by 2, 3 and 4 respectively, they add up to 74. Find these numbers.
• The ages of Rahul and Haroon are in the ratio 5:7. Four years later the sum of their ages will be 56 years. What are their present ages?
• The number of boys and girls in a class are in the ratio 7:5. The number of boys is 8 more than the number of girls. What is the total class strength?
• Baichung’s father is 26 years younger than Baichung’s grandfather and 29 years older than Baichung. The sum of the ages of all the three is 135 years. What is the age of each one of them?