[(-32) ÷ 8] ÷ 2 = -32 ÷ [8 ÷ 2]

Solution:

To prove the given expression is true or false let us compare the LHS and RHS parts individually.

On solving LHS,

[(-32) ÷ 8] ÷ 2 = -4÷2 = -2

On solving RHS,

-32 ÷ [8 ÷ 2] = -32 ÷ 4 = -8

Hence proved LHS ≠ RHS. Therefore the given statement is false.

✦ Try This: State whether the statement is true or false. [(-32) ÷ 16] ÷ 2 = -32 ÷ [16 ÷ 2].

We can apply integer rules and the order of operations to solve the given expression [(-32) ÷ 16] ÷ 2 = -32 ÷ [16 ÷ 2] and can easily analyse whether the statement is true or false.

☛ Also Check: NCERT Solutions for Class 7 Maths Chapter 1

NCERT Exemplar Class 7 Maths Chapter 1 Exercise Problem 106

[(-32) ÷ 8] ÷ 2 = -32 ÷ [8 ÷ 2].

Summary:

Applying the integer rules and PEMDAS, on simplifying we have proved that the LHS term is not equal to the RHS term. Hence the statement [(-32) ÷ 8] ÷ 2 = -32 ÷ [8 ÷ 2] is false.

☛ Related Questions:

• The sum of an integer and its additive inverse is zero (0)
• The successor of 0 × (-25) is 1 × (-25)
• Observe the following patterns and fill in the blanks to make the statements true: a. -5 × 4 = -20, . . . .