[(2/13)⁻⁶ ÷ (2/13)³]³ × (2/13)⁻⁹ = ___________. Fill in the blank to make the statement true.

Solution:

Given, [(2/13)⁻⁶ ÷ (2/13)³]³ × (2/13)⁻⁹ = ___________.

Using the law of exponents,

a^m ÷ aⁿ = a^{m - n}

From the given expression,

a = 2/13

m = - 6

n = 3

So, m - n = -6 - 3 = -9

[(2/13)⁻⁶ ÷ (2/13)³]³ = [(2/13)⁻⁹]³

Using the law of exponents,

(a^m)ⁿ = a^mn

Here, m = -9

n = 3

So, mn = (-9)3

= -27

(2/13)^-27 × (2/13)^-9 = (2/13)^-36

Therefore, the required value is (2/13)^-36.

✦ Try This: [(2/3)⁻³ ÷ (2/3)⁵]² × (2/3)⁻⁵ = ___________. Fill in the blank to make the statement true.

☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 12

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NCERT Exemplar Class 8 Maths Chapter 8 Problem 43

[(2/13)⁻⁶ ÷ (2/13)³]³ × (2/13)⁻⁹ = ___________. Fill in the blank to make the statement true.

Summary:

[(2/13)⁻⁶ ÷ (2/13)³]³ × (2/13)⁻⁹ = (2/13)^-36 makes the statement true

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☛ Related Questions:

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