Matrix Scalar Multiplication
Matrix scalar multiplication is multiplying a matrix by a scalar. A scalar is a real number whereas a matrix is a rectangular array of numbers. When we deal with matrices, we come across two types of multiplications:
- Multiplying a matrix by another matrix and is called "matrix multiplication"
- Multiplying a matrix by a scalar (a number) and is called "matrix scalar multiplication"
Let us learn how to do matrix scalar multiplication and its properties along with examples.
| 1. | What is Matrix Scalar Multiplication? | 
| 2. | Properties of Matrix Scalar Multiplication | 
| 3. | FAQs on Matrix Scalar Multiplication | 
What is Matrix Scalar Multiplication?
The matrix scalar multiplication is the process of multiplying a matrix by a scalar. Let 'A' be a matrix and 'k' be a scalar (real number). Then kA is the result of the matrix scalar multiplication. To find kA, we just multiply every element of A by 'k'. Here are some examples.
Example: If A = \(\left[\begin{array}{ll}
-1 & 2 \\
0 & 3
\end{array}\right]\) then
- 2A = 2 \(\left[\begin{array}{ll}
 -1 & 2 \\ \\
 0 & 3
 \end{array}\right]\) = \(\left[\begin{array}{ll}
 2(-1) & 2(2) \\ \\
 2(0) & 2(3)
 \end{array}\right]\) = \(\left[\begin{array}{ll}
 -2 & 4 \\ \\
 0 & 6
 \end{array}\right]\)
- (1/2) A = (1/2) \(\left[\begin{array}{ll}
 -1 & 2 \\ \\
 0 & 3
 \end{array}\right]\) = (1/2)\(\left[\begin{array}{ll}
 (1/2)-1 & (1/2)2 \\ \\
 (1/2)0 & (1/2)3
 \end{array}\right]\) = \(\left[\begin{array}{ll}
 -1/2 & 1 \\ \\
 0 & 3/2
 \end{array}\right]\)
- -A = -1 \(\left[\begin{array}{ll}
 -1 & 2 \\ \\
 0 & 3
 \end{array}\right]\) = \(\left[\begin{array}{ll}
 1 & -2 \\ \\
 0 & -3
 \end{array}\right]\)
- 0A = 0 \(\left[\begin{array}{ll}
 -1 & 2 \\ \\
 0 & 3
 \end{array}\right]\) = \(\left[\begin{array}{ll}
 0 & 0 \\ \\
 0 & 0
 \end{array}\right]\)
Thus, matrix scalar multiplication is mathematically defined as follows:
"If A = [aᵢⱼ] ₘ ₓ ₙ and k is a scalar then kA = k [aᵢⱼ] ₘ ₓ ₙ = [kaᵢⱼ] ₘ ₓ ₙ"
i.e., the element in ith row and jth column of kA is obtained by multiplying the corresponding element of A by 'k'. We can visualize this in the figure below.

Properties of Matrix Scalar Multiplication
If A and B are matrices of the same order; and k, a, and b are scalars then:
- A and kA have the same order.
 For example, if A is a matrix of order 2 x 3 then any of its scalar multiple, say 2A, is also of order 2 x 3.
- Matrix scalar multiplication is commutative. i.e., k A = A k.
- Scalar multiplication of matrices is associative. i.e., (ab) A = a (bA).
- The distributive property works for the matrix scalar multiplication as follows:
 k (A + B) = kA + k B
 A (a + b) = Aa + Ab (or) aA + bA
- The product of any scalar and a zero matrix is the zero matrix itself. For example:
 k \(\left[\begin{array}{ll}
 0 & 0 \\ \\
 0 & 0
 \end{array}\right]\) = \(\left[\begin{array}{ll}
 0 & 0 \\ \\
 0 & 0
 \end{array}\right]\)
- The product of -1 and A gives -A which is the additive inverse of A.
 For example, the additive inverse of \(\left[\begin{array}{ll}
 -1 & 2 \\ \\
 0 & 3
 \end{array}\right]\) is (-1) \(\left[\begin{array}{ll}
 -1 & 2 \\ \\
 0 & 3
 \end{array}\right]\) = \(\left[\begin{array}{ll}
 1 & -2 \\ \\
 0 & -3
 \end{array}\right]\).
☛ Related Topics:
Matrix Scalar Multiplication Examples
- 
Example 1: If the matrix A = \(\left[\begin{array}{c} 
 -18 \\
 -15\\
 21
 \end{array}\right]\) then what is the scalar multiple (-1/3)A?Solution: To find (-1/3) A, we have to multiply every element of A by (-1/3). Then (-1/3) A = \(\left[\begin{array}{c} 
 -1/3(-18) \\
 -1/3(-15)\\
 -1/3(21)
 \end{array}\right]\)= \(\left[\begin{array}{c} 
 6 \\
 5\\
 -7
 \end{array}\right]\)Answer: (-1/3) A = \(\left[\begin{array}{c} 
 6 \\
 5\\
 -7
 \end{array}\right]\).
- 
Example 2: If A = \(\left[\begin{array}{cc} 
 a & -2 \\ \\
 -3 & -2b
 \end{array}\right]\) and B = \(\left[\begin{array}{cc}
 5a & 2 \\ \\
 3 & 4b
 \end{array}\right]\), and A + B = 2I, where I is the identity matrix of order 2x2. Then find the values of a and b.Solution: 2I is the scalar multiple of the identity matrix I = \(\left[\begin{array}{ll} 
 1 & 0 \\
 0 & 1
 \end{array}\right]\). i.e., 2I = \(\left[\begin{array}{ll}
 2 & 0 \\
 0 & 2
 \end{array}\right]\).It is given that A + B = 2I \(\left[\begin{array}{cc} 
 a & -2 \\ \\
 -3 & -2b
 \end{array}\right]\) + \(\left[\begin{array}{cc}
 5a & 2 \\ \\
 3 & 4b
 \end{array}\right]\) = \(\left[\begin{array}{ll}
 2 & 0 \\ \\
 0 & 2
 \end{array}\right]\)\(\left[\begin{array}{ll} 
 6a & 0 \\ \\
 0 & 2b
 \end{array}\right]\) = \(\left[\begin{array}{ll}
 2 & 0 \\ \\
 0 & 2
 \end{array}\right]\)We will set the corresponding elements equal. 6a = 2 ⇒ a = 1/3 2b = 2 ⇒ b = 1 Answer: a = 1/3 and b = 1. 
- 
Example 3: If A = \(\left[\begin{array}{ll} 
 -5 & 1 & 3\\
 -4 & -2 & -1
 \end{array}\right]\) and B = \(\left[\begin{array}{ll}
 6 & -7 & 2\\
 0 & -8 & 3
 \end{array}\right]\), then find -2A + 3B.Solution: -2A + 3B = -2 \(\left[\begin{array}{ll} 
 -5 & 1 & 3\\
 -4 & -2 & -1
 \end{array}\right]\) + 3 \(\left[\begin{array}{ll}
 6 & -7 & 2\\
 0 & -8 & 3
 \end{array}\right]\)= \(\left[\begin{array}{ll} 
 10 & -2 & -6\\
 8 & 4 & 2
 \end{array}\right]\) + \(\left[\begin{array}{ll}
 18 & -21 & 6\\
 0 & -24 & 9
 \end{array}\right]\)= \(\left[\begin{array}{ll} 
 28 & -23 & 0\\
 8 & -20 & 11
 \end{array}\right]\)Answer: -2A + 3B = \(\left[\begin{array}{ll} 
 28 & -23 & 0\\
 8 & -20 & 11
 \end{array}\right]\).

FAQs on Matrix Scalar Multiplication
What is the Difference Between Matrix Scalar Multiplication and Matrix Multiplication?
Matrix scalar multiplication is multiplying a matrix by a scalar whereas matrix multiplication is multiplying two matrices. For any two matrices A and B, and for a scalar 'k', kA and kB represent the scalar multiplications of A and B respectively by k whereas AB represents the multiplication of matrices A and B.
How Do You Solve Matrix Scalar Multiplication?
The result of multiplying a matrix by a scalar is again a matrix of the same order where each of its elements is obtained by multiplying the corresponding elements of the original matrix by the scalar. For example, if P = \(\left[\begin{array}{ccc}
2 & -1 & 3 \\
0 & 5 & 2 \\
1 & -1 & -2
\end{array}\right]\) then
-3P
= (-3) \(\left[\begin{array}{ccc}
2 & -1 & 3 \\
0 & 5 & 2 \\
1 & -1 & -2
\end{array}\right]\)
= \(\left[\begin{array}{ccc}
-3(2) & -3(-1) & -3(3) \\
-3(0) & -3(5) & -3(2) \\
-3(1) & -3(-1) & -3(-2)
\end{array}\right]\)
= \(\left[\begin{array}{ccc}
-6 & 3 & -9 \\
0 & -15 & -6 \\
-3 & 3 & 6
\end{array}\right]\)
Can We Multiply a Matrix by a Scalar?
Yes, we can multiply a matrix by a scalar. For doing this, we just need to multiply every element of the matrix by the scalar. For example, if A = \(\left[\begin{array}{ccc}
2 & -1 & 3 \\ \\
0 & 5 & 2 \\ \end{array}\right]\) then 2A = \(\left[\begin{array}{ccc}
4 & -2 & 6\\\\
0 & 10 & 4 \\ \end{array}\right]\).
Can You Multiply a Matrix by 3?
A matrix can be multiplied by any scalar and hence it can be multiplied by 3 as well. For example, if A = \(\left[\begin{array}{ll}
1 & 2 \\
3 & 4 \\
5 & 1
\end{array}\right]\) then 3A = \(\left[\begin{array}{ll}
3 & 6 \\
9 & 12 \\
15 & 3
\end{array}\right]\).
Is Matrix Scalar Multiplication Commutative?
Yes, the matrix scalar multiplication is commutative. i.e., for any matrix M and a scalar 'a', we have aM = Ma. For example:
- 2 \(\left[\begin{array}{ll}
 1 & -1 \\
 2 & 1
 \end{array}\right]\) = \(\left[\begin{array}{ll}
 2 & -2 \\
 4 & 2
 \end{array}\right]\).
- \(\left[\begin{array}{ll}
 1 & -1 \\
 2 & 1
 \end{array}\right]\) 2 = \(\left[\begin{array}{ll}
 2 & -2 \\
 4 & 2
 \end{array}\right]\).
Can a Matrix be a Scalar?
No, a matrix cannot be a scalar. A matrix is a rectangular array of elements where the elements are arranged in rows and columns. A scalar is just a real number. Hence, a matrix cannot be a scalar.
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