When x = 3 and y = 5, by how much does the value of 3x² – 2y exceed the value of 2x² – 3y?

Solution:

Let the two functions be f(x, y) and g(x, y) such that f(x, y) = 3x² – 2y and g(x, y) = 2x² – 3y.

As given the value of f(x,y) exceeds, then let us evaluate the new value be h(x, y).

h(x, y) = f(x, y) - g(x, y)

h(x, y) = (3x² – 2y) – (2x² – 3y)

h(x, y) = x² + y

Also when x = 3 and y = 5,

h(3, 5) = (3)² + (5) = 9 + 5 = 14

Therefore, the value of 3x² – 2y exceeds the value of 2x² – 3y by 14.

When x = 3 and y = 5, by how much does the value of 3x² – 2y exceed the value of 2x² – 3y?

Summary:

The value of (3x² – 2y) exceeds the value of (2x² – 3y) when x = 3 and y = 5 by 14.