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What is the equation of the line, in slope-intercept form, that passes through (3, -1) and (-1, 5)?
Solution:
The equation of the line in slope-intercept form is given by y = mx + c ------(1)
Where, m = slope
c = y-intercept
The slope of the line can be found by using the formula m = (y2 - y1) / (x2 - x1)
Substituting the points (3, -1) and (-1,5) we get,
m = (5 + 1) / (-1 -3)
m = 6 / (-4)
m = -3/2
Next, find y-intercept using one of the points.
Let's take the point (-1,5)
5 = -3/2 (-1) + c
5 = 3/2 + c
c = 7/2
Put the value of c and m in (1)
y = -3/2(x) + 7/2
y = 1/2 [-3x + 7]
Therefore, the equation of line in slope-intercept form is y = 1/2 [-3x + 7].
What is the equation of the line, in slope-intercept form, that passes through (3, -1) and (-1, 5)?
Summary:
The equation of the line, in slope-intercept form, that passes through (3, -1) and (-1, 5) is y = 1/2 [-3x + 7].
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