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A day full of math games & activities. Find one near you.
What is the completely factored form of f(x) = x3 - 2x2 - 5x + 6?
Solution:
Given, f(x) = x3 - 2x2 - 5x + 6
We have to find the complete factored form of f(x).
Consider (x - 1) as a factor of f(x).
Let us check (x - 1) is a factor of f(x).
f(1) = (1)3 - 2(1)2 - 5(1) + 6
= 1 - 2 - 5 + 6
= 6 - 6
= 0
f(1) = 0
Therefore, (x - 1) is a factor of f(x) = x3 - 2x2 - 5x + 6.
By long division,
Now, find the factor of x2 - x - 6
x2 - x - 6 = 0
x2 - 3x + 2x - 6 = 0
x(x - 3) + 2(x - 3) = 0
(x + 2)(x - 3) = 0
Therefore, the factored form is (x - 1)(x + 2) and (x - 3).
What is the completely factored form of f(x) = x3 - 2x2 - 5x + 6?
Summary:
The completely factored form of f(x) = x3 - 2x2 - 5x + 6 is (x - 1)(x + 2) and (x - 3).
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