A day full of math games & activities. Find one near you.
A day full of math games & activities. Find one near you.
A day full of math games & activities. Find one near you.
A day full of math games & activities. Find one near you.
What is the 24th term of the arithmetic sequence where a1 = 8 and a9 = 56?
Solution:
Given a1 = 8 and a9 = 56
Let ‘a’ be the first term and ‘d’ be the common difference of the A.P. then
a1 = 8 = a --- (1)
a9 = a + (9 - 1)d
a9 = a + 8d = 56 --- (2)
Substituting (1) in (2) we get,
⇒ 8 + 8d = 56
⇒ 8d = 48
⇒ d = 6
a24 = a + 23d
= 8 + 23(6)
= 8 + 138
= 146
Therefore, the 24th term of the arithmetic sequence is 146.
What is the 24th term of the arithmetic sequence where a1 = 8 and a9 = 56?
Summary:
The 24th term of the arithmetic sequence where a1 = 8 and a9 = 56 is 146.
Math worksheets and
visual curriculum
visual curriculum