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A day full of math games & activities. Find one near you.
What is the 22nd term of the arithmetic sequence where a1 = 8 and a9 = 56?
Solution:
The nth term of an arithmetic sequence whose first term is a1 and common difference is d is
⇒ a1 + (n - 1)d
It is given that
a1 = 8 and a9 = 56
We know that
a9 = a1 + (9 - 1)d
8 + 8d = 56
8d = 56 - 8
8d = 48
d = 6
Now we have to find the 22nd term
a22 = a1 + (22 - 1)d
Substituting the values
a22 = 8 + (21)(6)
a22 = 8 + 126
So we get,
a22 = 134
Therefore, the 22nd term is 134.
What is the 22nd term of the arithmetic sequence where a1 = 8 and a9 = 56?
Summary:
The 22nd term of the arithmetic sequence where a1 = 8 and a9 = 56 is 134.
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