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Solution:
The given sequence is an arithmetic series with
First term a = 20
The common difference d = 16 - (20) = 12 - 16 = -4
The nth term of an arithmetic series is given by the expression:
Tn = a + (n-1)d
T₁₅ = 20 + (15 - 1)(-4)
T₁₅ = 20+ 14(-4)
T₁₅ = 20 - 56 = -36
T₁₅ = - 36
Summary:
The 15th term of the sequence 20, 16, 12 is -36