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Solution:
The sequence 64, 16, 4 ….is a geometric series with
Common ratio = r = 16/64 = 4/16 = 1/4
The first term is a = 64
The nth term of a geometric series is given as
Tn = arn - 1
T10 = 64(1/4)10 - 1
= 64(1/4)9
= 43 × 4-9
= 4-6
= 1/46
= 1/4096
Summary:
The 10th term of the sequence 64, 16, 4 is 1/46 or 1/4096