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A day full of math games & activities. Find one near you.
A day full of math games & activities. Find one near you.
What interval includes all possible values of x, where -3(6- 2x) ≥ 4x + 12?
(-∞,-3], [-3, ∞), (-∞, 15], [15, ∞)
Solution:
The given inequality is -3(6 - 2x) ≥ 4x + 12
Using the multiplicative distributive property
-18 + 6x ≥ 4x + 12
On rearranging
6x - 4x ≥ 12 + 18
2x ≥ 30
Dividing both sides by 2
x ≥ 15
We can see that as long as x is equal or more than 15 it will satisfy the equation.
The interval is [15, ∞)
Therefore, the interval which includes all possible values of x is [15, ∞).
What interval includes all possible values of x, where -3(6 - 2x) ≥ 4x + 12?
Summary:
The interval which includes all possible values of x, where -3(6 - 2x) ≥ 4x + 12 is [15, ∞).
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