Solve for \(b_{2}\) in A = 1/2h (\(b_{1}\) + \(b_{2}\)), if A = 16, h = 4, and \(b_{1}\) = 3

Let us change the subject of the equation and solve for \(b_{2}\)

Answer: The value of \(b_{2}\) = 5

Explanation:

We need to change the subject of the equation to \(b_{2}\)

A = 1/2 h(\(b_{1}\) + \(b_{2}\))

Substituting  A = 16 ; h = 4 ; \(b_{1}\) = 3

16  = 4/2 (3 + \(b_{2}\))

16 = 2(3 + \(b_{2}\))

8  = (3 + \(b_{2}\))

5 = \(b_{2}\)

Hence, solving for \(b_{2}\) in A = 1/2h (\(b_{1}\) +\(b_{2}\)), when A = 16, h = 4, and \(b_{1}\) = 3, gives \(b_{2}\) = 5