If the sum of two numbers is 21 and their difference is 5 then find the numbers.

Solution:

Given sum of two numbers is 21 and difference of them is 5

Let the two numbers be x,y

x + y = 21 --- [a]

x - y = 5 --- [b]

By elimination method, we get

⇒ 2x = 26

⇒ x = 13

Put x = 13 in eq[a], we get 13 + y = 21

⇒ y = 21 - 13

⇒ y = 8

Therefore, the two numbers are 13, 8.

If the sum of two numbers is 21 and their difference is 5 then find the numbers.

Summary:

If the sum of two numbers is 21 and their difference is 5 then the numbers are 13, 8.