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Solution:
Given,
P(a) = 0.62
P(b) = 0.47
P(a ∪ b) = 0.88
We have to find P(a ∩ b).
For mutually non-exclusive events, we know the probability formula as
P(a∩b) = P(a) + P(b) - P(a ∪ b)
= 0.62 + 0.47 - 0.88
= 1.09 - 0.88
= 0.21
Therefore, the value of P(a ∩ b) = 0.21
Summary:
If p(a) = 0.62, p(b) = 0.47, and p(a ∪ b) = 0.88, then p(a ∩ b) = 0.21