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If (6y - 11)(6y + 11) = ay2 - b, what is the value of a?
Solution:
Given: (6y − 11)(6y + 11) = ay2 − b -------------- (1)
To find: The value of 'a'
We will use the multiplication of algebraic expressions to solve the LHS of (6y − 11)(6y + 11) = ay2 − b
Let's solve the LHS = (6y − 11)(6y + 11)
Using the algebraic identity (a + b) (a - b) = a2 - b2 we get,
(6y − 11)(6y + 11) = 36y2 - 121
Now, comparing 36y2 - 121 with the RHS of equation (1) : ay2 − b
⇒ ay2 − b = 36y2 - 121
Thus, a = 36, b = 121
We can use Cuemath's online polynomial calculator to perform arithmetic operations on polynomials.
Thus, the value of 'a' for the given equation (6y − 11)(6y + 11) = ay2 − b is 36.
If (6y - 11)(6y + 11) = ay2 - b, what is the value of a?
Summary:
If (6y - 11)(6y + 11) = ay2 - b, the value of a is 36.
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