Given the function f(x) = 2x, find the value of f^-1(32).

Solution:

Inverse function is represented by f^-1 with regards to the original function f and the domain of the original function becomes the range of inverse function and the range of the given function becomes the domain of the

inverse function.

Given function:

f(x) = 2x

A function is a relation from a non-empty set B such that the domain of a function is A and no two distinct ordered pairs in f have the same first element.

let f(x) = y = 2x

x = y/2

x = f^-1(y)

f^-1(32) = 32/2 = 16

Given the function f(x) = 2x, find the value of f^-1(32).

Summary:

Given the function f(x) = 2x,the value of f^-1(32) is 16.