Find the vertex of the parabola whose equation is y = x² - 4x + 6.

Solution:

The vertex formula is x = -b/2a

The standard form of the quadratic equation is ax² + bx + c = 0

The given equation is

y = x² - 4x + 6

By comparing both

a = 1, b = -4, c = 6

Substituting it in the formula

x = - (-4)/ 2 (1) = 4/2 = 2

The vertex x point is at 2

(x, y) = (2, y)

Let us find the y point by inserting 2 at x

y = x² - 4x + 6

y = 2² - 4(2) + 6

y = 4 - 8 + 6

y = -4 + 6

y = 2

Therefore, the vertex is (2, 2).

Find the vertex of the parabola whose equation is y = x² - 4x + 6.

Summary:

The vertex of the parabola whose equation is y = x² - 4x + 6 is (2, 2).