A day full of math games & activities. Find one near you.
A day full of math games & activities. Find one near you.
A day full of math games & activities. Find one near you.
A day full of math games & activities. Find one near you.
Find the terminal point p(x, y) on the unit circle determined by the given value of t.
t = -7π/6, p(x, y) = (-3/√2, -1/2).
Solution:
We have any point (x, y) on the unit circle of radius ‘r’ centered at origin which is (rcosθ, rsinθ)/(rcost, rsint).
Here, t = -7π/6 and r = 1
∴ Required point (x, y) = (rcost, rsint)
= [(1)cos (-7π/6), (1)sin(-7π/6)]
= [cos 7π/6, -sin7π/6] [∵ cos(-θ) = cosθ and sin (-θ) = -sinθ]
Using allied angles,
cos(7π/6) = cos [π + (π/6)] = - cos(π/6) = -√3/2
-sin(7π/6) = -sin [π+ (π/6)] = -[-sin(π/6)] = 1/2
Therefore, the required point is (-√3/2, 1/2)
Find the terminal point p(x, y) on the unit circle determined by the given value of t.
t = -7π/6, p(x, y) = (-3/√2, -1/2).
Summary:
The terminal point p(x, y) on the unit circle determined by the given value of t, t = -7π/6, p(x, y) = (-3/√2, -1/2) is (-√3/2, 1/2).
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