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A day full of math games & activities. Find one near you.
A day full of math games & activities. Find one near you.
Find the equation for a circle given center at (-1,-2) & passes through the point (15,-2)?
Solution:
If the a point P(x, y) lies on the circle with the centre at (h, k) then the general equation of the circle will be written as
\(\sqrt{(x-h)^{2} + (x-k)^{2}} = a\)
where a is the radius
The radius of the circle is calculated using the distance formula as:
\(\sqrt{(15-(-1)^{2} + (-2-(-2))^{2})}\) = \(\sqrt{256 +0}\) = 16
The general equation of the circle can be therefore written as :
\(\sqrt{(x-(-1)^{2} + (y-(-2))^{2}} = 16\)
Squaring both the sides and solving we get the general equation of the circle asl
x2 + 1 + 2x + y2 + 4 + 4y = 256
x2 + y2 + 2x + 4y - 251 = 0
Find the equation for a circle given center at (-1,-2) & passes through the point (15,-2)?
Summary:
The equation of the circle with center (-1,-2) and containing the point (15,-2) is x2 + y2 + 2x + 4y - 251 = 0
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