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A day full of math games & activities. Find one near you.
A day full of math games & activities. Find one near you.
Find the dimensions of a rectangle with a perimeter 108m whose area is as large as possible.
Solution:
It is given that
Perimeter of the rectangle = 108m
Area is as large as possible if both the values are the same number.
In order to have a maximum area in a rectangle, the dimensions should be equal.
Consider the dimensions as x
So perimeter can be written as
2 (x + x) = 108
2 (2x) = 108
By further calculation
4x = 108
Divide both sides by 4
x = 27
Therefore, the dimensions of a rectangle is 27m × 27m.
Find the dimensions of a rectangle with a perimeter 108m whose area is as large as possible.
Summary:
The dimensions of a rectangle with a perimeter 108m whose area is as large as possible is 27m × 27m.
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