A day full of math games & activities. Find one near you.
A day full of math games & activities. Find one near you.
Solution:
It is given that
sin2x + sin x = 0, [0, 2π)
Let us take sin x as common
sin x(sin x + 1) = 0
sin x = 0
So we get
x = 0, (π - 0), (π + 0), (2π - 0)
or
sin x + 1 = 0
sin x = -1
x = π + π/2
x = 0, 3π/2, π
Therefore, all the solutions are x = 0, 3π/2, π.
Summary:
All solutions in the interval [0, 2π). sin2x + sin x = 0 are x = 0, 3π/2, π.