A rectangular solid has sides of 7 cm, 9 cm, and 11 cm. What is its surface area?

Solution:

Given, a rectangular solid of sides 7cm, 9cm and 11cm.

We have to find the surface area of a rectangular solid.

The surface area of a rectangular solid is given by

A = 2(xy+yz+zx)

Where, x, y and z are the dimensions of the rectangular solid.

Here, x=7, y=9 and z=11.

Surface area, A = 2[(7×9) + (9×11) + (11×7)]

A = 2[63 + 99 + 77]

A = 2[239]

A = 478 square centimeters.

Therefore, the surface area of rectangular solid is 478 square centimeters.

A rectangular solid has sides of 7 cm, 9 cm, and 11 cm. What is its surface area?

Summary:

A rectangular solid has sides of 4cm, 6cm and 8cm. Its surface area is 478 square centimeters.