x + y = 3.3, 0.6/3x - 2y = -1. 3x -2y ≠ 0, solve the equation

Solution:

From the above question, we have the linear equations as,

x + y = 3.3-----------(1)

0.6/3x - 2y = -1.

By cross multiplication

0.6 = -3x + 2y

3x - 2y = -0.6--------(2)

Multiplying (1) by 2 and by adding with (2)

5x = 6

x = 6/5

x = 1.2

Substituting the value of x in (1),

1.2 + y = 3.3

y = 3.3 - 1.2

y = 2.1.

x = 1.2

y = 2.1.

Therefore, x = 1.2 and y = 2.1.

✦ Try This: Solve the following equation: x + y = 3.5, 0.6/3x - 2y = -5. 3x -2y ≠ 0

☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 3

NCERT Exemplar Class 10 Maths Exercise 3.3 Problem 9 (i)

x + y = 3.3, 0.6/3x - 2y = -1. 3x -2y ≠ 0, solve the equation

Summary:

Solving the following equation x + y = 3.3, 0.6/3x - 2y = -1. 3x -2y ≠ 0, we get x = 1.2 and y = 2.1

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