x/3 + y/4 = 4. 5x/6 - y/8 = 4, solve the equation

Solution:

From the above question, we have the linear equations as,

x/3 + y/4 = 4.

4x + 3y = 48.---------------(1)

5x/6 - y/8 = 4.

20x - 3y = 96.--------------(2)

Adding (1) and (2),we get,

24x = 144

x = 6.

Substituting the value of x in (1),we get,

4 x 6 + 3y = 48

3y = 48 - 24

3y = 24

y = 8.

x = 6.

y = 8.

Therefore, the required values of x and y are 6 and 8, respectively.

✦ Try This: Solve the following equation: x/3 + y/4 = 6. 5x/6 - y/8 = 6

☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 3

NCERT Exemplar Class 10 Maths Exercise 3.3 Problem 9 (ii)

x/3 + y/4 = 4. 5x/6 - y/8 = 4, solve the equation

Summary:

Solving the following equation x/3 + y/4 = 4. 5x/6 - y/8 = 4, we get the required values of x and y as 6 and 8, respectively

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