When a = 0, b = -1, find the value of the given expressions:
(i) 2a + 2b   (ii) 2a² + b² + 1   (iii) 2a²b + 2ab² + ab
(iv) a² + ab + 2

Solution:

According to the question, the value of 'a' is given as 0 and 'b' is -1.

Let us substitute the values given in the following expressions.

(i) 2a + 2b

= (2 × 0) + 2 × (-1)

= 0 + (-2)

= -2 is the required value.

(ii) 2a² + b² +1

= 2 × 0² + (-1)² + 1

= 0 + 1 + 1

= 2 is the required value.

(iii) 2a²b + 2ab² + ab

= 2 × 0 × 0 × (-1) + 2 × 0 × (-1)² + 0 × (-1)

= 0 + 0 + 0

= 0 is the required value.

(iv) a² + ab + 2

= 0² + 0 × (-1) + 2

= 0 + 0 + 2

= 2 is the required value.

☛ Check: NCERT Solutions for Class 7 Maths Chapter 12

Video Solution:

When a = 0, b = -1, find the value of the given expressions: (i) 2a + 2b (ii) 2a² + b² + 1 (iii) 2a²b + 2ab² + ab (iv) a² + ab + 2

Maths NCERT Solutions Class 7 Chapter 12 Exercise 12.3 Question 5

Summary:

When a = 0, b = -1, the value of the given expressions are : (i) 2a + 2b = -2 (ii) 2a² + b² + 1 = 2 (iii) 2a²b + 2ab² + ab = 0 (iv) a² + ab + 2 = 2

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