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What is the perimeter of each of the following figures? What do you infer from the answers?

Solution:

We know that perimeter is defined as the sum of all its sides.

(a) Side = 25 cm

⇒ 4 × 25 = 100 cm

Therefore, perimeter of the square is 100 cm.

(b) Length(L )= 40, Breadth(B) = 10

⇒ 2 (40 + 10)

⇒ 2 × 50 = 100 cm

Therefore, perimeter of the rectangle is 100 cm.

(c) Length(L ) = 30, Breadth(B) = 20

Perimeter of rectangle = 2 (L + B)

⇒ 2 (30 + 20)

⇒ 2 × 50 = 100 cm

Therefore, perimeter of the rectangle is 100 cm.

(d) Perimeter of triangle = Sum of all the sides

= 30 + 30 + 40

= 100 cm

Therefore, perimeter of the triangle is 100 cm.

Thus, we observe that the perimeters of all the given figures are 100 cm. Hence, all the figures have equal perimeters.

NCERT Solutions for Class 6 Maths Chapter 10 Exercise 10.1 Question 16

Summary:

We have found that the perimeter of each of the given figures is 100 cm. Hence, all the figures have equal perimeters.

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