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Two years ago, Salim was thrice as old as his daughter and six years later, he will be four years older than twice her age. How old are they now

Solution:

Let us consider Salim age as x years

Let us consider his daughter’s age to be y years.

From the first condition,

Salim was thrice as old as his daughter two years ago

x - 2 = 3(y - 2)

x - 2 = 3y - 6

x - 3y = -4-----------(1)

From the second condition,

Salim will be four years older than twice her age six years later

x + 6 = 2(y + 6) + 4

x + 6 = 2y + 12 + 4

x -2y = 16 - 6

x - 2y = 10-----------(2)

Solve equations (1) and (2) now.

Subtract (1) from (2),

y = 14.

Substitute y in (2),

x - 2 x 14 = 10

x = 10 + 28

x = 38

So we get

x = 38

y = 14.

Therefore, Salim and his daughter’s age is 38 years and 14 years respectively.

✦ Try This: Two years ago, Salim was twice as old as his daughter and six years later, he will be four years older than twice her age. How old are they now

☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 3

NCERT Exemplar Class 10 Maths Exercise 3.3 Problem 16

Two years ago, Salim was thrice as old as his daughter and six years later, he will be four years older than twice her age. How old are they now

Summary:

Two years ago, Salim was thrice as old as his daughter and six years later, he will be four years older than twice her age. Salim and his daughter’s age is 38 years and 14 years respectively.

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