The loss per cent on selling 140 geometry boxes at the loss of S.P. of 10 geometry boxes is equal to _________

Solution:

Let the selling price (SP) of one geometry box be = x

SP of 10 geometry boxes = 10x

SP of 140 geometry boxes = 140x

Loss made by selling 140 geometry boxes = 10x

Therefore the cost price (CP) of 140 geometry boxes is

= SP of 140 geometry boxes + loss (SP of 10 geometry boxes)

= 140x + 10x

= 150x

The loss percent on selling 140 geometry boxes is:

= (10x/150x) × 100

= 100/15

= 6 ⅔%

✦ Try This: The loss per cent on selling 120 geometry boxes at the loss of S.P. of 12 geometry boxes is equal to _________.

Let the selling price (SP) of one geometry box be = x

SP of 12 geometry boxes = 12x

SP of 120 geometry boxes = 120x

Loss made by selling 120 geometry boxes = 12x

Therefore the cost price (CP) of 120 geometry boxes is

= SP of 120 geometry boxes + loss (SP of 12 geometry boxes)

= 120x + 12x

= 132x

The loss percent on selling 120 geometry boxes is:

= (12x/132x) × 100

= (12/132) × 100

= (1/11) × 100

= 9 1/9 %

☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 8

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NCERT Exemplar Class 8 Maths Chapter 9 Problem 39

The loss per cent on selling 140 geometry boxes at the loss of S.P. of 10 geometry boxes is equal to _________

Summary:

The loss per cent on selling 140 geometry boxes at the loss of S.P. of 10 geometry boxes is equal to 6 ⅔%

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