The cost price of 10 tables is equal to the sale price of 5 tables. The profit per cent in this transaction is _________
Solution:
Let the selling price (SP) of one table = Rs. x
SP of 5 tables = 5x
Therefore,
Cost price(CP) of 10 tables = SP of 5 tables = 5x
The selling price of 10 tables = 10x
The profit made by selling ten tables = 10x - 5x = 5x
Profit percentage = (Profit/Cost Price) × 100
= (5x/5x) × 100
= 100%
✦ Try This: The cost price of 10 tables is equal to the sale price of 8 tables. The profit per cent in this transaction is _________.
Let the selling price of one table = Rs. x
Selling price of 8 tables = 8x
Therefore,
Cost price of 10 tables = selling price of 8 tables = 8x
The selling price of 10 tables = 10x
The profit made by selling ten tables = 10x - 8x = 2x
Profit percentage = (Profit/Cost price) × 100
= (2x/8x) × 100
= 25%
☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 8
NCERT Exemplar Class 8 Maths Chapter 9 Problem 40
The cost price of 10 tables is equal to the sale price of 5 tables. The profit per cent in this transaction is _________
Summary:
The cost price of 10 tables is equal to the sale price of 5 tables. The profit per cent in this transaction is 100%
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