The angle of elevation of the top of a vertical tower from a point on the ground is 60°. From another point 10 m vertically above the first, its angle of elevation is 45°. Find the height of the tower
Solution:
Given, the angle of elevation of the top of a vertical tower from a point on the ground is 60°
From another point vertically above the first, the angle of elevation is 45š©
We have to find the height of the tower.
Let AP be the vertical tower.
Height of the vertical tower, AP = 10m
Angle of elevation, ∠TPO = 60š©
Angle of elevation of another point, ∠TAB = 45š©
From the above diagram,
OB = AP = 10m
Let us consider,
Distance from the point of observation to the foot of the tower, PO = x m
Total height of the tower, TO = h m
From the figure, TB = (h - 10)m
Considering the ∠TPO, we get,
tan60š© = TO/PO
Since, tan60° = √3
√3 = h/x
x = h/√3--------------(1)
Considering the ∠TAB, we get,
tan45° = TH/AB
tan45° = TO - TH/AB
Since, tan45° = 1,
1 = h - 10/AB
AB = h -10
x = h -10-----------------(2)
Comparing (1) and (2), we get,
h/√3 = h -10
h - h/√3 = 10
h(1 - 1√3) = 10
h(√3 - 1/√3) = 10
h = 10√3/√3 - 1
Taking conjugate,
h = 10√3/√3 - 1 × √3 - 1/√3 - 1
h = 30 + 10√3/3 - 1
h = 30 + 10√3/2
h = 15 + 5√3
h = 5(3 + √3)
h = 5√3 (√3 + 1)
Therefore, the height of the tower is 5√3 (√3 + 1)m.
ā¦ Try This: From a point on the ground, 20 m away from the foot of a vertical tower, the angle of elevation of the top of the tower is 60°, what is the height of the tower?
ā Also Check: NCERT Solutions for Class 10 Maths Chapter 8
NCERT Exemplar Class 10 Maths Exercise 8.4 Problem 16
The angle of elevation of the top of a vertical tower from a point on the ground is 60°. From another point 10 m vertically above the first, its angle of elevation is 45°. Find the height of the tower
Summary:
The angle of elevation of the top of a vertical tower from a point on the ground is 60° . From another point 10 m vertically above the first, its angle of elevation is 45š©. The height of the tower is 5√3 (√3 + 1)m
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