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The age of A is five years more than that of B. 5 years ago, the ratio of their ages was 3:2. Find their present ages.

Solution:

Given, the age of A is five years more than that of B.

5 years ago, the ratio of their ages was 3 : 2

We have to find the present ages of A and B.

Let the present age of B be x years

The present age of A is 5 + x years

Five years ago,

Age of A = (5 + x) - 5

= x years

Age of B = x - 5 years

According to the question,

x/(x - 5) = 3/2

2(x) = 3(x - 5)

2x = 3x - 15

By transposing,

2x - 3x = -15

-x = -15

x = 15

Now, 5 + x = 5 + 15 = 20 years

Therefore, the present ages of A and B are 20 years and 15 years.

✦ Try This: The age of Anu is six years more than that of Sheela. 4 years ago, the ratio of their ages was 2:5. Find their present ages.

☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 2

NCERT Exemplar Class 8 Maths Chapter 4 Problem 97

Summary:

The age of A is five years more than that of B. 5 years ago, the ratio of their ages was 3:2. Their present ages are 20 years and 15 years

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