Solve the following equations:
(a) 10p = 100 (b) 10p + 10 = 100 (c) p/4 = 5
(d) −p/3 = 5 (e) 3p/4 = 6 (f) 3s = –9
(g) 3s + 12 = 0 (h) 3s = 0 (i) 2q = 6
(j) 2q – 6 = 0 (k) 2q + 6 = 0 (l) 2q + 6 = 12
Solution:
We use the basic concepts of simple linear equations to solve the questions given.
(a) 10p = 100
Dividing both the sides by 10 we get,
10p/10 = 100/10
p = 10
(b) 10p + 10 =100
Subtracting 10 from both sides we get,
10p + 10 − 10 = 100 −10
10p = 90
Dividing both the sides by 10 we get,
10p/10 = 90/10
p = 9
(c) p/4 = 5
Multiplying both the sides by 4 we get,
(p/4) × 4 = 5 × 4
p = 20
(d) − p/3 = 5
Multiplying both the sides by -3 ,
(−p/3) × (-3) = 5 × (-3)
p = -15
(e) 3p/4 = 6
Multiplying both the sides by 4, we get
(3p/4) × 4 = 6 × 4
3p = 24
Dividing both the sides by 3 we get,
3p/3 = 24/3
p = 8
(f) 3s = -9
Dividing both the sides by 3,
3s/3 = -9/3
s = -3
(g) 3s + 12 = 0
Subtracting 12 from both the sides of the equation we get,
3s + 12 - 12 = 0 - 12
3s = -12
Dividing both the sides by 3 we get,
3s/3 = -12/3
s = - 4
(h) 3s = 0
Dividing both the sides by 3 we get,
3s/3 = 0/3
s = 0
(i) 2q = 6
Dividing both the sides by 2 we get,
2q/2 = 6/2
q = 3
(j) 2q - 6 = 0
Adding 6 to both sides of the equation we get,
2q - 6 + 6 = 0 + 6
2q = 6
Dividing both the sides by 2 we get,
2q/2 = 6/2
q = 3
(k) 2q + 6 = 0
Subtracting 6 from both the sides of the equation we get,
2q + 6 − 6 = 0 - 6
2q = - 6
Dividing both the sides by 2 we get,
2q/2 = - 6/2
q = -3
(l) 2q + 6 =12
Subtracting 6 from both the sides of the equation we get,
2q + 6 − 6 = 12 - 6
2q = 6
Dividing both the sides by 2 we get,
2q/2 = 6/2
q = 3
☛ Check: NCERT Solutions Class 7 Maths Chapter 4
Video Solution:
Solve the following equations: (a) 10p = 100 (b) 10p + 10 = 100 (c) p/4 = 5 (d) −p/3 = 5 (e) 3p/4 = 6 (f) 3s = –9 (g) 3s + 12 = 0 (h) 3s = 0 (i) 2q = 6 (j) 2q – 6 = 0 (k) 2q + 6 = 0 (l) 2q + 6 = 12
NCERT Solutions for Class 7 Maths Chapter 4 Exercise 4.2 Question 4
Summary:
We have solve the following equations: (a) 10p = 100 (b) 10p + 10 = 100 (c) p/4 = 5 (d) −p/3 = 5 (e) 3p/4 = 6 (f) 3s = –9 (g) 3s + 12 = 0 (h) 3s = 0 (i) 2q = 6 (j) 2q – 6 = 0 (k) 2q + 6 = 0 (l) 2q + 6 = 12 and the solutions are as follows:(a) p = 10 ,(b) p = 9, (c) p = 20, (d) p = −15 , (e) p = 8 , (f) s = - 3, (g) s = - 4, (h) s = 0 , (i) q = 3 , (j) q = 3 , (k) q = - 3, (l) q = 3
☛ Related Questions:
- Give First The Step You Will Use To Separate The Variable And Then Solve The Equation A X 1 0 B X 1 0 C X 1 5 D X 6 2 E Y 4 7 F Y 4 4 G Y 4 4 H Y 4 4
- Give First The Step You Will Use To Separate The Variable And Then Solve The Equation A 3l 42 B B 2 6 C P 7 4 D 4x 25 E 8y 36 F Z 3 5 4 G A 5 7 15 H 20t 10
- Give The Steps You Will Use To Separate The Variable And Then Solve The Equation A 3n 2 46 B 5m 7 17 C 20 P 3 40 D 3 P 10 6
- Solve The Following Equations A 2y 5 2 37 2 B 5t 28 10 C A 5 32 D Q 4 75 E 5 2 X 5 F 5 2 X 25 4
visual curriculum