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Solve Q.1 of Exercise 3.1 by the method of substitution
Aftab tells his daughter, “Seven years ago, I was seven times as old as you were then. Also, three years from now, I shall be three times as old as you will be.” (Isn’t this interesting?) Represent this situation algebraically and graphically

Solution:

Let Aftab is x years old and his daughter is y years old

Given; Seven years ago,

x - 7 = 7 (y - 7)

x - 7y + 42 = 0 be equation 1

Three years from now,

x + 3 = 3(y + 3)

x - 3y - 6 = 0 be equation 2

From equation 2, we get

x = 3y + 6 be equation 3.

Substitute the value of x = 3y + 6 in equation 1.

(3y + 6) - 7y + 42 = 0

- 4y + 48 = 0

Adding 4y to both the sides we get

4y = 48

Divide both the sides by 4.

y = 12

Substitute the value y = 12 in equation 2.

x = 3(12) + 6

x = 42

☛ Check: NCERT Solutions for Class 10 Maths Chapter 3

Solve Q.1 of Exercise 3.1 by the method of substitution. Aftab tells his daughter, “Seven years ago, I was seven times as old as you were then. Also, three years from now, I shall be three times as old as you will be.” (Isn’t this interesting?) Represent this situation algebraically and graphically

Summary:

Aftab’s age is 42 years old and his daughter’s age is 12 years old as seven years ago, he was seven times as old as his daughter was then. Also, three years from now, he will be three times as old as she will be

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