Solve:
(i) 2 - (3/5) (ii) 4 + (7/8) (iii) (3/5) + (2/7)
(iv) (9/11) - (4/15) (v) (7/10) + (2/5) + (3/2)
(vi) \(2{\Large\frac{2}{3}}\) + \(3{\Large\frac{1}{2}}\) (vii) \(8{\Large\frac{1}{2}}\) - \(3{\Large\frac{5}{8}}\)
Solution:
Let's use the concept of addition and subtraction of fractions here.
(i) 2 - (3/5)
2 - 3/5
= 2/1 - 3/5
= (10 - 3)/5
= 7/5
(ii) 4 + (7/8)
= 4 + 7/8
= 4/1 + 7/8
= (32 + 7)/8
= 39/8
(iii) (3/5) + (2/7)
= 3/5 + 2/7
= (21 + 10)/35
= 31/35
(iv) (9/11) - (4/15)
= 9/11 - 4/15
= (135 - 44)/165
= 91/165
(v) (7/10) + (2/5) + (3/2)
= 7/10 + 2/5 + 3/2
= (7 + 4 + 15)/10
= 26/10
= 13/5
(vi) \(2{\Large\frac{2}{3}}\) + \(3{\Large\frac{1}{2}}\)
= 8/3 + 7/2
= (16 + 21)/6
= 37/6
(vii) \(8{\Large\frac{1}{2}}\) - \(3{\Large\frac{5}{8}}\)
= 17/2 - 29/8
= (68 - 29/8)
= 39/8
☛ Check: NCERT Solutions for Class 7 Maths Chapter 2
Video Solution:
Solve: (i) 2 - (3/5) (ii) 4 + (7/8) (iii) (3/5) + (2/7) (iv) (9/11) - (4/15) (v) (7/10) + (2/5) + (3/2) (vi) \(2{\Large\frac{2}{3}}\) + \(3{\Large\frac{1}{2}}\) (vii) \(8{\Large\frac{1}{2}}\) - \(3{\Large\frac{5}{8}}\)
NCERT Solutions Class 7 Maths Chapter 2 Exercise 2.1 Question 1
Summary:
The values of the following: (i) 2 - (3/5) (ii) 4 + (7/8) (iii) (3/5) + (2/7) (iv) (9/11) - (4/15) (v) (7/10) + (2/5) + (3/2) (vi) \(2{\Large\frac{2}{3}}\)+ \(3{\Large\frac{1}{2}}\) (vii) \(8{\Large\frac{1}{2}}\) - \(3{\Large\frac{5}{8}}\) are (i) 7/5 (ii) 39/8 (iii) 31/35 (iv) 91/165 (v) 13/5 (vi) 37/6 and (vii) 39/8 respectively.
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