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A day full of math games & activities. Find one near you.
Solve each of the equation in Exercises 6 to 9: 21x² – 28x + 10 = 0
Solution:
The given quadratic equation can be written as,
21x² – 28x + 10 = 0
By comparing this with ax2 + bx + c = 0, we get a = 21, b = -28, and c = 10.
Its discriminant is, D = b2 - 4ac = (-28)2 - 4(21)(10) = -56
The solutions of the given quadratic equation are,
(- b ± √D)/2a = 28 ± √(-56) ) / 2(21)
= (28 ± i√56) / 42 [∵ √- 1 = i]
= (28 ± 2i√14) / 42
= 2/3 ± (√14/21) i
Hene the solutions of the given equation are x = 2/3 + i√14/ 21, 2/3 - i√ 14 / 21
NCERT Solutions Class 11 Maths Chapter 5 Exercise ME Question 9
Solve each of the equation in Exercises 6 to 9: 21x² – 28x + 10 = 0
Summary:
The solutions of 21x² – 28x + 10 = 0 are x = 2/3 + i√14 / 21, 2/3 - i√ 14/ 21
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