Rewrite the following rational numbers in the simplest form:
(i) -8/6 (ii) 25/45 (iii) -44/72 (iv) -8/10
Solution:
To solve the given question we will find the H.C.F of numerator and denominator and then divide both the numerator and denominator by the H.C.F.
After dividing it we will get the simplest form of the rational number.
(i) -8/6
H.C.F of 8 and 6 is 2.
Dividing the numerator and denominator by H.C.F, we get,
(-8/2) / (6/2) = -4/3
(ii) 25/45
H.C.F of 25 and 45 is 5.
Dividing the numerator and denominator by H.C.F, we get,
(25/5) / (45/5) = 5/9
(iii) - 44/72
H.C.F of 44 and 72 is 4. Dividing the numerator and denominator by H.C.F, we get,
(-44/4) / (72/4) = -11/18
(iv) - 8/10
H.C.F of 8 and 10 is 2. Dividing the numerator and denominator by H.C.F, we get,
(-8/2) / (10/2) = -4/5
☛ Check: NCERT Solutions for Class 7 Maths Chapter 9
Video Solution:
Rewrite the following rational numbers in the simplest form: (i) -8/6 (ii) 25/45 (iii) -44/72 (iv) -8/10
Class 7 Maths NCERT Solutions - Chapter 9 Exercise 9.1 Question 7
Summary:
The following rational numbers in the simplest form: (i) -8/6 (ii) 25/45 (iii) -44/72 (iv) -8/10 is written as (i) -4/3 (ii) 5/9 (iii) -11/18 (iv) -4/5
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